© J R Stockton, ≥ 2007-02-06

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This page is ancillary mainly to Gravity Page 2, Kepler, where it originated.

See also
(10)
Kepler and His Laws *ff.*, by
Dr. David P. Stern, GSFC.

By a dictionary definition, an ellipse is the figure produced when a cone is cut by a plane making smaller angle with the base than the side of the cone makes (COD 1970).

The cone can in fact be a cylinder, and so an ellipse is a stretched circle, from which its Cartesian form follows.

An ellipse is defined in plane geometry (Chambers: directrix,
eccentricity) as the set of points *(X, Y)* such that the distance
*R* from a given point F, termed the focus, is *e* times the
distance of the point from a fixed line, the Directrix.

*R = L / (1 - e cos θ)*

*(X/a) ^{2} + (Y/b)^{2} = 1*

An ellipse could also be defined as the path of a point whose distances R & R' from two fixed foci F & F' have a constant sum.

This section is being worked upon, in the hope that it will be useful in discussing Kepler.

The order in which the parts of the diagram should be generated depends upon the definition chosen.

An ellipse is the locus of points for which *R = eZ*
where *R* is the distance from a given point F, *e*
is a given constant, and *Z* is the distance from a given line, the
directrix.

Let the distance between directrix and F be *f* ; then
*f + R cos θ = Z = R/e* ,
and so
*R = ef / (1 - e cos θ)* ,
the polar equation with *L = ef* .

Put the *X* axis through F and perpendicular to the directrix;
put the origin O on it at a distance greater by *ae* where *a*
is an unknown constant. Let the directrix be
at *X = -D* ; then *Z = D+X* .

Setting *Y = 0* gives

Apoapsis : `R // +X : `
* X _{a} + ae = R = e(D + X_{a})*

Periapsis :

Those are satisfied by the choices

Setting *X = 0* in the definition
now gives *R = a* then Pythagoras gives
*b = Y = a(1 - e ^{2})^{½}*
then applying him to a general point

Since that has no odd terms in *X*, by symmetry there must be
another directrix at *X = +D* and a point F' at
*X = +ae* such that *R' = e(D-X)* . Thus
*R + R' = e(D+X) + e(D-X) = 2eD =2a* , so an ellipse can be
drawn with two pins, a loop of thread, and a pencil.

An ellipse is the locus of points for which
*(X/a) ^{2} + (Y/b)^{2} = 1* where

The distance *R* from a point on the ellipse to the point
*(-aE, 0)* satisfies
*R ^{2} = (X+aE)^{2} + Y^{2}* ;
replace

Focus-to-centre FO : *ae*

Semi-latus rectum *L* : *Y* at *X = -ae* :
*L = b(1-e ^{2})^{½}* :

Apoapsis FA :

Periapsis FP :

so :

An ellipse is the locus of points for which
*R = L / (1 - e cos θ)* ;
*L*, given by *θ =
± π/2*, is the semi-latus rectum.
Mirror-symmetry across the line
*θ* = 0 is obvious, and
*R cos θ = (R-L)/e* .

Now *cos θ = (Z-K)/R* for some *K*, so

*
R = L / (1 - e (Z-K)/R) →
R - e (Z-K) = L →
R = e (Z-K-L/e) * ;

thus the perpendicular at *K = L / e*
from F is a directrix.

The extremes of *R* occur when
*cos θ = ±1* ; thus

Major axis : *2a = R _{max} + R_{min} =
L / (1-e) + L / (1+e) = 2L / (1-e^{2})* ;
symmetry across this axis is obvious from the symmetry of

Minor axis : differentiating, the maximum of

Consider two equal curves of unknown shape given by
*R = L / (1 - e cos θ)* and
*R' = L / (1 - e cos θ')*,
with the angles being measured at F from a line FF'
and at F' from the reverse line F'F. They are symmetrical about
*θ*=0 and will be mirror images of
each other in the perpendicular bisector of FF'. For a point common to
both curves, FF' will equal the sum of the projections of the radii
onto the line.

*FF' = R cos θ
+ R' cos θ' =
(R-L)/e + (R'-L)/e = (R+R'-2L)/e*

That must prove something.

Take a loop of string of total length *2a(1+e)* and two pins a
distance *2ae* apart; *R+R'* is constant.

Since *R+R'* is constant, wave optics implies focusing of rays
from one focus onto the other.

Since *R+R'* is constant, the tangent to the ellipse at that
point makes the same angle with each of them; then geometrical optics
implies focusing.

These are alternative views of the same situation.